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Lepton
1:41+ Arse Scratcher
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Posted: Fri Mar 08, 2002 4:09 am Post subject: 1 |
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a^2 + b^2 = c^2
3^2 + 4^2 = 5^2
.......Everyone knows Pythagores' Theorem.
a^3 + b^3 + c^3 = d^3
3^3 + 4^3 + 5^3 = 6^3
........Fancy, eh?
What does d^3 signify?
(I don't know the answer myself) |
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Chuck
Daedalian Member
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Posted: Fri Mar 08, 2002 4:54 am Post subject: 2 |
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| Mere coincidence. It means nothing. |
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Bicho the Inhaler
Daedalian Member
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Posted: Fri Mar 08, 2002 4:59 am Post subject: 3 |
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| "There are no coincidences in the natural numbers." or something to that effect, said by someone or other famous. |
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daniel801
Daedalian Member
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Posted: Fri Mar 08, 2002 5:12 pm Post subject: 4 |
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| it means that three ice cubes of sides 3, 4, and 5 when melted would fit in an ice cube tray with side 6 |
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daniel801
Daedalian Member
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Posted: Fri Mar 08, 2002 6:51 pm Post subject: 5 |
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...if re-frozen  |
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Lepton
1:41+ Arse Scratcher
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Posted: Sat Mar 09, 2002 4:36 am Post subject: 6 |
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| But no funky trigangle-y goodness? |
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groza528
No Place Like Home
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Posted: Sat Mar 09, 2002 7:31 am Post subject: 7 |
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| Not that I know of (displays title) |
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Suspence
Daedalian Member
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Posted: Sat Mar 09, 2002 3:05 pm Post subject: 8 |
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I found the quote to which Mr. Inhaler refers:
"Achilles: An "infinite coincidence"? Among the natural numbers, NOTHING is coincidental-nothing happens without there being some underlying pattern. "
It has to mean something somewhere...but what???
------------------
I hate people who try to write interesting things in their signature
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Bicho the Inhaler
Daedalian Member
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Posted: Sat Mar 09, 2002 6:19 pm Post subject: 9 |
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| Yes, page 398 of Hoftstadter's GEB. That must have been it. |
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Coyote

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Posted: Sat Mar 09, 2002 10:37 pm Post subject: 10 |
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http://mathforum.org/dr.math/problems/toscano7.14.97.html
I don't really understand why Fermat's Last Theorem being proven implies that no formula for finding solutions to a^3+b^3+c^3=d^3 exists, but if it's true, I doubt there'll be any 'practical' application similar to the Pythagorean Theory.
The article lists several other solutions to the equation though, just in case anyone wants to look them over and try to figure out some kind of connecting idea to them. |
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dave10000
Tinhorn
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Posted: Sun Mar 10, 2002 5:06 am Post subject: 11 |
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For no good reason, I wrote the following Mathematica program:
While[
(a = Random[Integer, {1000, 1500}]) ||
(b = Random[Integer, {1000, 1500}]) ||
(c = Random[Integer, {1000, 1500}]) ||
!IntegerQ[(a^3 + b^3 + c^3)^(1/3)]]
Print[a]
Print[b]
Print[c]
Print[(a^3 + b^3 + c^3)^(1/3)]
In under 2 minutes of run time, my computer told me that:
1004^3 + 1219^3 + 1332^3 = 1731^3 |
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