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R.E.M.
Icarian Member
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 Posted: Thu Apr 11, 2002 7:08 pm Post subject: 1 |
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| What is the lowest whole number (larger than 1) which is a factor of ((10^9^8^7^6^5^4^3^2^2002)+11)+(((10^9^8^7^6^5^4^3^2^2002)+11)x4)? |
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Orbiting
very ign-o-rable
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| Posted: Thu Apr 11, 2002 7:09 pm Post subject: 2 |
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erm...5?
-o-
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groza528
No Place Like Home
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| Posted: Thu Apr 11, 2002 7:15 pm Post subject: 3 |
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| If it isn't 5 it's 3. I should be able to figure out for sure, give me a moment |
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groza528
No Place Like Home
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| Posted: Thu Apr 11, 2002 7:15 pm Post subject: 4 |
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wait, I thought the ^ was *  Might take two moments |
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groza528
No Place Like Home
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| Posted: Thu Apr 11, 2002 7:17 pm Post subject: 5 |
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| The number will be 500000000...0055. So 3. |
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Orbiting
very ign-o-rable
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| Posted: Thu Apr 11, 2002 7:43 pm Post subject: 6 |
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bah @ intuitive math.
you are right.
-o-
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Qball
In the Quorner Pocket
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| Posted: Thu Apr 11, 2002 11:43 pm Post subject: 7 |
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wow.... hint please?
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CrystyB
Misunderstood Guy
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| Posted: Fri Apr 12, 2002 1:04 am Post subject: 8 |
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| Let N=9^8^7^6^5^4^3^2^2002. So x=(10^N+11)+((10^N+11)*4)=(10^N+11)*5. N is so unimaginable BIG that the 1 in front is very far away from the 11 in the end. So no overlapping, and since 3 divides anything whose sum of digits is (in this case 15) divisible by 3, there you have it. |
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