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groza528
No Place Like Home
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impossibleroot
Hi-Keeba!
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Posted: Thu Nov 18, 2004 1:17 am Post subject: 42 |
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| Sounds like Skinny waited until the white raven *didn't* exist anymore... |
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Guest
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Posted: Thu Nov 18, 2004 1:23 am Post subject: 43 |
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Ok, so assuming we've gotten over notion that anything _could_ be considered evidence, and also assuming there is no preconceived notion that ravens are black:
1. So he has a box with every raven in existence in it, and grabs one, right? Well, its definately evidence that _some_ ravens are black, but statistically it doesn't prove much. If he grabbed 3, 4, or even 100 ravens and they were all black, it would then become evidence that all ravens are black because you have eliminated to a large extent that the raven was picked by chance, and that there are not in fact ravens of all colors.
2. even less-so evidence than #1, because there is no element of chance involed: skinny picked whatever raven he wanted. It could be the only black raven in existence and all others are white.
3. Nope, once again the statistics thing. And whats a representitive universe? Anything even close will still be huge, so one element out of say 15 billion is insignificant.
5. Although my answer was the same for both, I would say that #1 is much closer to being evidence that all ravens are black than #3 is, mostly because there are far fewer ravens than non-black objects (even in a representitive universe), so any raven will be statistically more significant.
6. Actually its the opposite (seeing one card out of a full deck and knowing it is red actually increases the probability that the second card will be black. While the first card has a probability of being red = 50%, the second will have a probability being 26/51 ~50.9%). _BUT_ this requires knowing something about decks of cards to be relevent, so that argument is invalid.
8. I disagree. Firstoff, these statements (p->q, ~q->~p [the contrapositive]) are being looked at as mathematical comparisons, but in the context they are invalid. Showing that some non-black objects are non-ravens is not the same nor is it evidence to the statement "all non-black objects are non-ravens." Going back to the argument that we only need evidence and not proof, 'evidence' (by your definition) is not established until some statistically significant number of 'non-black non-ravens' or 'black ravens' have been presented.
I go back to the very simple argument that if I have you guess what color a glurtz is and show you a non-glurtz (of any color), there is no way that you can tell me what color a glurtz is nor can you tell me that they are all the same color. Because what I showed you does not help you decide what color a glurtz is nor does it give you any reason to assume they are all the same color, it is not evidence. |
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austinap
Daedalian Member
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Posted: Thu Nov 18, 2004 1:30 am Post subject: 44 |
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| The above was my post, and the probability given for the second card (~50.99%) is the probability for the next card being _black_. the probability for it being red would be 25/51, ~49.01% instead of 50%. |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 1:46 am Post subject: 45 |
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| even less-so evidence than #1 |
Gah! See, this is where the conversation breaks down, people. This seems to concede that the situation in #1 *is* evidence, else how could #2 be less. But your argument in #1 seemed to argue it's not evidence at all.
The question is not whether it's good or substantial evidence, the question is whether it's ANY evidence. I'm all for having a good debate on this, but let's please try to state our positions clearly.
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| he grabbed 3, 4, or even 100 ravens and they were all black, it would then become evidence that all ravens are black because you have eliminated to a large extent that the raven was picked by chance |
What does "eliminated to a large extent" mean? Is your position (approximately) that if something makes something 1% more likely than it's not evidence, but if it makes it 50% more likely it is?
To make the tough question even tougher -- does one black raven make it, to ANY extent, more likely that all ravens are black? |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 1:52 am Post subject: 46 |
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| Actually its the opposite (seeing one card out of a full deck and knowing it is red actually increases the probability that the second card will be black. While the first card has a probability of being red = 50%, the second will have a probability being 26/51 ~50.9%). _BUT_ this requires knowing something about decks of cards to be relevent, so that argument is invalid. |
You either misunderstood, or you're wrong. If you don't know anything about the 2 cards, there's only (about) a 25% chance they're both red. If you turn one over and it's red, there's now (about) a 50% chance that both are red.
Finding out that one is red makes it more likely than before that both are red. Does that mean that turning one (out of two) over and finding it red is *evidence* that both are red? What about one out of 3? One out of 3 jelly beans (of previously unknown color)? One out of a million jelly beans (of previously unknown color)? Is there a line? |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 2:18 am Post subject: 47 |
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How about the following? I'm curious to see what people think. (Assume no trickery, such as color-changing cubes, language tricks, forcing your choices so that they're not really random, etc.)
I have a box with 2 items in it. They are enclosed in plastic spheres, so you can't tell them apart by touch. You feel inside that there are indeed 2 items. I then put a red cube (in a similar plastic sphere) into the box. I claim that all cubes in the box right *now* are red. You know, because you saw, that the box contains at least one red cube.
Q1. You pull an item from the box, and it is a red cube. Does that increase the strength of your belief, to any degree, that all cubes in the box when I said "now" were red? Why or why not?
Q2. Now, with 2 items remaining in the box, you pull another item out of the box. It is a blue pyramid. Does *that* increase the strength of your belief, to any degree, that all cubes in the box when I said "now" were red? Why or why not? |
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Guest
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Posted: Thu Nov 18, 2004 4:45 am Post subject: 48 |
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| Finding out that one is red makes it more likely than before that both are red. Does that mean that turning one (out of two) over and finding it red is *evidence* that both are red? What about one out of 3? One out of 3 jelly beans (of previously unknown color)? One out of a million jelly beans (of previously unknown color)? Is there a line? |
It makes it more likely that BOTH are red, but less likely that the next card is red... I misread the question. As far as the line, thats admittedly pretty vague. I would say it would have to be well under a 50% chance that the items drawn were drawn by chance alone. (do a chi-squared test, etc). And at that point, it would only be enough 'evidence' to consider the possibility strongly enough to look into it. I wouldn't say _real_ evidence for it being true would occur until you got under the 5-10% mark.
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even less-so evidence than #1
Gah! See, this is where the conversation breaks down, people. This seems to concede that the situation in #1 *is* evidence, else how could #2 be less. But your argument in #1 seemed to argue it's not evidence at all.
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Meaning it is even further from being evidence. One random statistic isnt evidence, because variance plays too large a role, but by taking more samples, the chances that the results are strictly chance is lowered, and if the variance is lowered enough, it could reach a point where it could be helpful in making a decision about something.
You're arguing a moot point about when something becomes evidence. I think its pretty obvious that what skinny offers in the problem isnt evidence to any rational person. Also, your examples are much different than the original question because they are over-simplified and completely change the significance of drawing 1 item. Choosing 1 item out of 3 is on a completely different scale than drawing 1 item out of 15 billion. Also, you changed the example by drawing conclusions about something that is there by seeing something that is there, where the original question asks us to draw conclusions about what something is by what something else is not.
Also, why do you keep ignoring this argument:
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| I go back to the very simple argument that if I have you guess what color a glurtz is and show you a non-glurtz (of any color), there is no way that you can tell me what color a glurtz is nor can you tell me that they are all the same color. Because what I showed you does not help you decide what color a glurtz is nor does it give you any reason to assume they are all the same color, it is not evidence. |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 5:24 am Post subject: 49 |
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| You're arguing a moot point about when something becomes evidence. |
Um, it's hardly moot. It's kind of the point of the puzzle.
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| Choosing 1 item out of 3 is on a completely different scale than drawing 1 item out of 15 billion. |
I think everyone would agree with that. But why doesn't that simply mean that 1/3 is much BETTER evidence than 1/15000000000? Why is one evidence and the other not evidence at all?
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| Also, why do you keep ignoring this argument: |
I didn't ignore it, it didn't make the triage list in the limited time I had to respond. But here goes:
You have it backward. I'm not showing you non-ravens, I'm showing you non-black objects. Thus, I'm not showing you non-Glurtzes, I'm showing you non-black objects. Suppose, instead of showing you non-Glurtzes, I showed you all non-black objects in the universe. If none of them was a Glurtz, then you'd know that the statement "all Glurtzes are black" was correct. (If you disagree with that, we have to start from square 1.) The question is, then, if I showed you 99% of all non-black objects in the universe would you feel pretty good about the statement "all Glurtzes are black"? 99.99999% of all non-black objects? All non-black objects in the universe except one? Surely you'd admit (wouldn't you?) that if I randomly showed you all non-black objects in the universe except one, and they were all non-Glurtzes, you'd feel pretty good that the final one was a non-Glurtz, too. But if that's the case, you should feel pretty good that all Glurtzes were black. The question is, then, what percentage of non-black objects do you need to see to feel pretty good about the statement "all non-black objects are non-Glurtzes." And, doesn't every non-black non-Glurtz you see up until that point contribute a bit to that feeling? If not, don't you concede that, at some point along the line, a non-black non-Glurtz tips the balance from you not feeling pretty good to you feeling pretty good? And thus, doesn't that same non-black non-Glurtz do the same thing about your belief in the statement "all Glurtzes are black"? |
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Guest
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Posted: Thu Nov 18, 2004 5:54 am Post subject: 50 |
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You still missed the point.
The point was that you can tell me nothing about the object even after I showed you a different object and made some claim that something about it wasn't the same as a glurtz. If it were evidence, you could form some sort of conclusion (or at least, an inkling of an idea) of some property of a glurtz, but obviously you cant. I could say something like "all glurtz' are round," show you some sort of non-round object and promise it wasn't a glurtz, and you still would have no idea what shape a glurtz was. The only idea you'd have would be my word that all glurtz' are round. The fact that I showed you a non-round object that wasn't a glurtz is completely insignificant. A glurtz could still be round.
Also, there was nothing in the passage to indicate that the object shown was chosen at random. Given those circumstances, skinny could show you 99.9999% of all non-black objects in the universe and still not have given evidence that all ravens are black, because all objects were shown at his discretion. The biggest part of this is that the item was not chosen at random. Had the item been chosen at random, I suppose by some twist of the imagination the item _could_ be conceived as evidence, though I still would argue that because you could make no useful conclusions from that 'evidence.' |
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austinap
Daedalian Member
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Posted: Thu Nov 18, 2004 6:09 am Post subject: 51 |
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I keep forgetting to log in again
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"something shown to a person in support of a claim, that the person did not previously know of, that increases the person's belief in the truth of the claim to any degree."
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By this, I don't think it takes much to see that 1/15billion random non-black objects not being a raven won't increase anyone's belief that all ravens are black, however 1/3 would probably increase most peoples belief in the truth of the claim. By this definition, whether something is evidence or not depends on the person (which doesn't make it the best definition in this case). But can you honestly tell me that someone showing you a beer bottle would increase your belief that all ravens are black?
First of all, the implications p->q and ~q->~p are "for all" statements (ALL ravens are black, ALL non-black objects are non-ravens), so in the case of one object its meaningless.
Anyways, let p = "it is a raven" and q="it is black," then what we are given is ~q and we are trying to make some deduction about p. The only deduction we can make by knowing (~q) is true is that (~p) must also be true (if all ravens are indeed black). So, all we know is that the object he showed us is not a raven. |
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austinap
Daedalian Member
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Posted: Thu Nov 18, 2004 6:28 am Post subject: 52 |
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Correcting myself here:
We can make no deduction at all from what skinny gave us. Again, let p='it is a raven' and q='it is black.'
skinny's statement was "all non-black things are non-ravens" (~q->~p). (~q) is true, but we still can't conclude anything about ~p. For all we know, he could be lying. Reducing this statement, we get (~q->~p)<=>(q or ~p) or "it is black or it is not a raven." Because q is false, this reduces simply to ~p. What skinny said wasn't necessarily true, it is only true if all ravens are indeed black but doesn't force them to be any more likely to be black. He proved it to you as much as saying "all ravens are black" would prove it to you. |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 6:39 am Post subject: 53 |
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| If it were evidence, you could form some sort of conclusion (or at least, an inkling of an idea) of some property of a glurtz |
Not true. Perhaps none exist.
The statements:
(1) All unicorns are white.
(2) All unicorns are black.
are (vacuously) true. Neither of them allows you to conclude that a white unicorn or a black unicorn exists.
If I showed you ALL non-black, non-Glurtzes (and you knew I showed you all of them) , then you would KNOW that the statement "all Glurtzes are black" is true, even though you would not know whether any black Glurtzes existed.
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| Also, there was nothing in the passage to indicate that the object shown was chosen at random. |
Um, yes there was. I expressly made the point that I was showing you non-black objects randomly selected (read again). I did not repeat it every time, but the selections made in my example about Glurtzes were always intended to be random.
If your point is that Skinny did not choose the brown bottle at random in the original puzzle, yeah, I pointed that out long ago, and it's a fatal flaw. That's why the questions I've posted more recently expressly ask about what happens when objects *are* chosen at random, and from a small and definite number. That makes the tough parts of the problem stand out more clearly. In particular, try addressing the issues in my Post # 46. |
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austinap
Daedalian Member
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Posted: Thu Nov 18, 2004 6:46 am Post subject: 54 |
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Well, your post 46 questions were pretty obvious, but they don't fall along the same lines as the puzzle does. And as far as stating that the object wasn't chosen randomly, I was referring to the original puzzle.
BUT, I did give a mathematical proof which applies even to randomly chosen objects (assuming you follow the along the lines of the puzzle and chose only 1 object).
stating again (letting p = "it is a raven" and q="it is black"), and we are given q = false and asked to solve for p (in the equation ~q->~p), so we have:
~q -> ~p <=> q or ~p
and since q = false, we have
q or ~p <=> ~p.
We can make no conclusion about p in this equation given what we are given.
Now, your comeback to this would be that we're given ~p = true, so therefore this is a true statement, and you would be correct. This also means nothing. Because this is a true statement, we can re-arrange things again and again, only to find out that what skinny showed us is not a raven. This is because anything he is telling us is about this object alone, not non-ravens or non-black objects in general. |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 4:37 pm Post subject: 55 |
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| We can make no conclusion about p in this equation given what we are given. |
Yes, but that's different. We are not asking about a positive conclusion about p, but rather only whether an item is "evidence" of p.
Note, if I show you a black raven, or even a million black ravens, you cannot conclude with certainty that all ravens are black. The question is only whether my item or items can act as "evidence."
Note also -- the Skinny puzzle starts from the premise that one black raven *is* evidence (but very scant) of the proposition that "all ravens are black." If you reject that principle, then of course you will not consider a non-black non-raven to be evidence.
If you take issue with a black raven as being "evidence" that all ravens are black, let's find another word you will accept. "suggestive of"? "helps confirm"? "increases the likelihood that"? whatever it is, let's call it "X"
Then the puzzle is, if one black raven is X of the statement "all ravens are black," why isn't one non-black non-raven (chosen at random from the universe of non-black objects) X of the statement "all non-black objects are nonravens" (which is equivalent to the statement "all ravens are black").
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| Well, your post 46 questions were pretty obvious, but they don't fall along the same lines as the puzzle does. |
Well, that's a cop-out, to use a phrase from the 1960's. I can't tell from your response what you think the answers to Q1 and Q2 are. Since I'm interested, would you care to explain? I concede the questions are different from the original puzzle, but I believe they are a starker form of the "paradox" (loosely defined) that the original puzzle is designed to illustrate. Because what happens when we increase the number of objects in the box by 1. By 1,000,000? If we make the number of cubes equal to the number of ravens in the universe, and the number of non-cubes 1,000,000 times that number? Doesn't it start to become the original puzzle, or at least one interpretation of the original puzzle (under the harder condition, not stated in the original puzzle, that Skinny chose the bottle at random from non-black objects)? |
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Oscar
Daedalian Member
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Posted: Thu Nov 18, 2004 8:02 pm Post subject: 56 |
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Note also -- the Skinny puzzle starts from the premise that one black raven *is* evidence (but very scant) of the proposition that "all ravens are black." If you reject that principle, then of course you will not consider a non-black non-raven to be evidence.
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Dave, as I stated earlier, a black raven is *not* evidence that all ravens are black if the search method is to find all black items and test for their raven-ness That way the theory can never fail, hence such exhibits are not evidence.
From everything else you've said, however, I suspect we are in agreement on the fundamental nature of the 'puzzle' being the way in which the 'evidence' is sought. Skinny's brown bottle was almost certainly produced because of it's bottle-ness (i.e. non-raven-ness) not because of it's brown-ness (i.e. non-black-ness) Testing a bottle's colour could not fail the theory, but testing something brown for being a raven could. |
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dave10000
Tinhorn
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Posted: Thu Nov 18, 2004 9:24 pm Post subject: 57 |
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| Dave, as I stated earlier, a black raven is *not* evidence that all ravens are black if the search method is to find all black items and test for their raven-ness |
I fully agree, nor did I say otherwise. It *is* something (query whether it's "evidence") to search for ravens and test for their blackness. But, as several papers on the subject point out, what is one to do when a raven shows up on your doorstep and becomes an observed fact? You note the blackness and ravenness at the same time. Is that evidence or not? (My example, intentionally, did not say how the black raven came into one's knowledge.)
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| Skinny's brown bottle was almost certainly produced because of it's bottle-ness (i.e. non-raven-ness) not because of it's brown-ness (i.e. non-black-ness) Testing a bottle's colour could not fail the theory, but testing something brown for being a raven could. |
Even worse, I suspect. If Skinny knows in advance that there are no ravens in the bar (a reasonable assumption), then *nothing* he selects in the bar could serve as exemplar "evidence" of "all ravens are black."
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| From everything else you've said, however, I suspect we are in agreement on the fundamental nature of the 'puzzle' being the way in which the 'evidence' is sought. |
I agree. |
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austinap
Daedalian Member
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Posted: Thu Nov 18, 2004 9:27 pm Post subject: 58 |
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First off, here's my answer to your two questions:
Q1: This could probably be considered evidence, though still weak evidence given that there is a 1/3 chance it is the same cube I just saw you throw it. However, due to the limited number of objects and the fact that is saying something about what it itself is (a red cube), it doesn't much apply to the ravens problem.
Q2. Obviously it increases the strength of my belief that all items in the box are not red cubs. It only takes one counter-example to disprove a statement.
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Yes, but that's different. We are not asking about a positive conclusion about p, but rather only whether an item is "evidence" of p.
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I didn't say positive conclusion, I said conclusion. The conclusion that this bottle is 'evidence' of all ravens being black is one possible conclusion that we could not reach. All we can say from being given the bottle is that it is not a raven. Like I previously mentioned, he is taking a 'for all' statement and using it as an if-them statement. "All ravens are black" or the contrapositive "all non-black things are non-ravens" are statements in set theory. "If this is not black, it is not a raven" is a statement in boolean algebra. They are related statements, but not equivalent.
I'm assume we are all in agreement that the bottle could _never_ be considered evidence because of the way it was chosen. However, I still argue that even if the bottle was chosen at random, you still cannot derive any useful information about ravens from it.
That aside, I am in complete agreement with everything Oscar said. Skinny's wager fails on many levels. |
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dave10000
Tinhorn
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Posted: Fri Nov 19, 2004 1:34 am Post subject: 59 |
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I asked:
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| Q2. Now, with 2 items remaining in the box, you pull another item out of the box. It is a blue pyramid. Does *that* increase the strength of your belief, to any degree, that all cubes in the box when I said "now" were red? Why or why not? |
You responded:
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| Q2. Obviously it increases the strength of my belief that all items in the box are not red cubs. It only takes one counter-example to disprove a statement. |
That simply does not answer the question I asked.
* * *
I can see why you are reluctant to answer the question I did ask. Your answer is probably "yes." But it probably strikes you odd that a blue pyramid can increase your belief in the truth of "all cubes are red," since it seems to go against your view that:
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| All we can say from being given the bottle is that it is not a raven. |
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dave10000
Tinhorn
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Posted: Fri Nov 19, 2004 1:54 am Post subject: 60 |
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I think this is as stark as I can make it:
The 1000 ravens experiment.
Given: I have exactly 1000 ravens in this box.
Given: I have exactly 1000 nonblack things in this box.
Note that those groups can overlap. Perhaps the box contains exactly 1000 white ravens. Or perhaps it contains 500 white ravens, 500 black ravens and 500 red ballons. Or perhaps it contains 1000 black ravens and 1000 blue balloons. You get the point.
Q1: If I pull an item out of the box and it's a black raven, that gets me 1/1000 of the way to the statement "all ravens in the box are black." If I did that 999 more times, I'd be sure of the statement. Let's call that a milliconfirmation. Is a milliconfirmation "evidence" that "all ravens in the box are black"?
Q2: If I pull an item out of the box and it's a green shoe, that gets me 1/1000 of the way to the statement "all nonblack objects in the box are nonravens." If I did that 999 more times, I'd be sure of the statement. So, it's a milliconfirmation of "all nonblack objects in the box are nonravens," according to our definition of "milliconfirmation" in Q1. Is it "evidence" that "all nonblack objects in the box are nonravens"?
Q3: If your answers to Q1 and Q2 are different, why? (Be specific)
Q4: If your answers to Q1 and Q2 are different, then is the green shoe of Q2, which is by definition a milliconfirmation of "all nonblack objects in the box are nonravens," also a milliconfirmation of "all ravens in the box are black"? If not, why not? (Be specific)
Q5: If your answers to Q1 and Q2 are the same, and if Skinny can prove that he picked a brown bottle at random from all things within 100 miles of him (he was picking at random from all things -- not all ravens, or all nonravens, or all nonblack things), then did Skinny win the bet? If not, why not? (Be specific) |
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Guest
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Posted: Fri Nov 19, 2004 2:43 pm Post subject: 61 |
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| dave10000 wrote: |
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| Q2. Obviously it increases the strength of my belief that all items in the box are not red cubs. It only takes one counter-example to disprove a statement. |
That simply does not answer the question I asked.
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The question you asked:
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| Q2. Now, with 2 items remaining in the box, you pull another item out of the box. It is a blue pyramid. Does *that* increase the strength of your belief, to any degree, that all cubes in the box when I said "now" were red? Why or why not? |
You said 'now' at the beginning, with the 3 items in the box, one known to be a red cube. How would finding a blue pyramid in the box convince me that all items in the box _WERE_ red cubes? It is a complete disproof that all items were red cubes. If you rephrased your question to ask if it made me think that all items _NOW_ in the box are red cubes, the answer could be different.
Ill get your other questions later, I have class. |
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dave10000
Tinhorn
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Posted: Fri Nov 19, 2004 3:58 pm Post subject: 62 |
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| How would finding a blue pyramid in the box convince me that all items in the box _WERE_ red cubes? |
I did not ask whether all the *items* were red cubes, I asked whether all the *cubes* were red. If the box originally contained 2 red cubes and one blue pyramid, then it would be true that all the cubes originally in the box were red. Thus, after Q2, if the remaining item in the box is a red cube or any non-cube, then the statement "all original cubes were red" is true. If the remaining item in the box is a non-red cube, then the statement "all original cubes were red" is false.
The question is, does finding the blue pyramid increase your belief as to the truth of the statement?
(If you think "no", consider this: if there were 1,000,000 objects in the box to begin with, and you pulled 999,999 out at random and they were all red cubes and blue pyramids, wouldn't you feel pretty good about the truth of the statement "all cubes originally in the box were red"? Seems like there's only a 1 in a million chance that the statement is false. And if #999,999 was a blue pyramid, didn't that help the odds go from 2 in a million to 1 in a million? Doesn't similar logic apply (on a smaller scale) when the box only had 3 objects originally?) |
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Celt
still thinking
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Posted: Fri Nov 19, 2004 4:20 pm Post subject: 63 |
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| dave10000 wrote: |
| Q1: If I pull an item out of the box and it's a black raven, that gets me 1/1000 of the way to the statement "all ravens in the box are black." If I did that 999 more times, I'd be sure of the statement. Let's call that a milliconfirmation. Is a milliconfirmation "evidence" that "all ravens in the box are black"? |
Yes.
| dave10000 wrote: |
| Q2: If I pull an item out of the box and it's a green shoe, that gets me 1/1000 of the way to the statement "all nonblack objects in the box are nonravens." If I did that 999 more times, I'd be sure of the statement. So, it's a milliconfirmation of "all nonblack objects in the box are nonravens," according to our definition of "milliconfirmation" in Q1. Is it "evidence" that "all nonblack objects in the box are nonravens"? |
Yes.
| dave10000 wrote: |
| Q5: If your answers to Q1 and Q2 are the same, and if Skinny can prove that he picked a brown bottle at random from all things within 100 miles of him (he was picking at random from all things -- not all ravens, or all nonravens, or all nonblack things), then did Skinny win the bet? If not, why not? (Be specific) |
Yes. Skinny won his bet.
And furthermore, producing a black raven IS evidence that all ravens are black and producing a red card at random from a deck is evidence to support the proposition that all cards in the deck are red. |
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Rio
Guest
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Posted: Fri Nov 19, 2004 6:41 pm Post subject: 64 |
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This has been a very interesting thread. Taking a slightly different approach, consider the following situation:
You and Skinny are walking around town, many miles from home. It begins to rain. As you duck into a coffee shop you wonder aloud whether all of your cats are inside your house. Skinny says "So you're wondering whether all of the cats that belong to you are inside your house? I have evidence that they are!" You are delighted. "What evidence?", you say. "Well," says Skinny triumphantly, "this cup of coffee isn't in your house!" You feel so relieved...
Basically, the problem is that the information provided by Skinny does not differentiate between the two possible states of affairs that might obtain: (P1) that all your cats are in your house, and (P2) that at least one of your cats is outside. P1 and P2 are contradictory - they cannot both be true. Skinny's information, if it were evidence for the one, would be evidence against the other. Since this is not the case, Skinny's information cannot be construed as evidence for either scenario.
The same holds true for (R1) All ravens are black, and (R2) at least one raven is non-black. The existence of a brown bottle, by itself, constitutes neither confirming nor disconfirming evidence for either scenario, and hence Skinny must lose the bet. |
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dave10000
Tinhorn
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Posted: Fri Nov 19, 2004 7:03 pm Post subject: 65 |
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Celt --
I tend to agree.
In the original puzzle, though, it is pretty clear that Skinny did *not* pick the bottle at random from all things within 100 miles of him. Rather, he (1) picked an object from inside the bar, where he presumably knew no ravens existed, and (2) presented you with an item, after he examined it and knew that it was a nonblack nonraven. In that event, I firmly believe that the brown bottle, in the original puzzle as given, did not qualify as evidence that "all ravens are black" (or of "all non-black objects are non-ravens"). I expect you agree. Do you?
* * *
And a request to the poster of the official solution, when it is posted:
PLEASE address the fact that Skinny intentionally picked an object he knew not to be a raven -- he did *not* pick an object at random that had some chance of falsifying the claim. Since that is the case, what Skinny chose did NOT qualify as evidence.
To see why, consider that if we allow Skinny to intentionally pick an object that is consistent with the claim, then he could provide evidence of almost anything. For instance, suppose he made the bet "I can produce evidence that all people named Joe have red hair." If he then went out and searched until he found a guy named Joe with red hair, THAT would not be evidence, since the purported evidence was not selected at random. (Joe *might* be viewed as an intentionally selected "confirming example," but a confirming example that is not selected at random is not evidence.) Unless the official response addresses the fact that Skinny's selection was not at random and was designed so that it was incapable of being inconsistent with the claim, then the solution will be incomplete at best (and wrong at worst). |
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Celt
still thinking
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Posted: Fri Nov 19, 2004 8:34 pm Post subject: 66 |
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| dave10000 wrote: |
| I expect you agree. Do you? |
For the most part yes, but we probably differ on the following scenario.
Imagine a person asks you to turn over the top card on a deck. It's the ace of spades. "I'm not surprised", says the person. "It's a trick deck. They are all the ace of spades". I would consider the card you turned over to be evidence that backs up the person's clam. I suspect you would not.
Also I believe that an item chosen at random in a bar which is non-black and raven-sized is likely to be a beer bottle. |
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dave10000
Tinhorn
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Posted: Fri Nov 19, 2004 9:22 pm Post subject: 67 |
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| Quote: |
| Imagine a person asks you to turn over the top card on a deck. It's the ace of spades. "I'm not surprised", says the person. "It's a trick deck. They are all the ace of spades". I would consider the card you turned over to be evidence that backs up the person's clam. I suspect you would not. |
I was originally going to say that your suspicion was correct, and indeed started writing that. Partway, I stopped. I find this question to be difficult (at least at first). Here's what I think:
I do NOT think that it is evidence that the deck is a trick deck. I DO think it is evidence that the deck is entirely Aces of Spades. (By "evidence," I mean that I am more inclined to believe the claim after learning of the thing than before learning of the thing.)
This is, I think, how I see it. Before the evidence, perhaps I think there is a 99% chance the deck is true and a 1% chance the deck is trick. (In reality, probably 99.999%, but I'm simplifying.) The 1% is spread over many possibilities -- 52 spade aces, 52 heart aces, 52 club nines, etc. -- so maybe I think there's a 0.02% chance of all Aces of Spades. After I see the Ace, I don't adjust my view about whether the deck is a trick deck, but now I know that if it *is* all the same card, it can only be Aces of Spades. Thus, the situation is:
Before seeing the card, my belief is:
99% regular deck, 1% trick deck (of which 0.02% is all Aces of spades)
After seeing the card, my belief is:
99% regular deck, 1% all Aces of Spades
Thus:
The card did not increase my belief of there being a trick deck, but did increase my belief of there being all Aces of Spades.
Or, substituting a definition:
The card was not evidence of a trick deck, but was evidence of the deck being all Aces of Spades.
I'm comfortable with this analysis, but it did take me a while to get there. |
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Celt
still thinking
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Posted: Sat Nov 20, 2004 1:42 am Post subject: 68 |
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I understand what you mean, but I don't think anyone else will.
It appears we are in agreement then, other than the random selection thing. |
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Guest
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Posted: Sun Nov 21, 2004 6:20 pm Post subject: 69 |
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I had another idea. Say a man's wife has been missing for some time, and he is on trial for her murder. If the prosecution shows only that the man had purchased a large life insurance policy on her a week before, this would not be considered evidence that a crime was even committed. If however the prosecutor produced additional information (blood stained carpet, her blood on his clothes, history of violent fights,etc.), then the insurance policy would be evidence - but only when considered in context with the other facts. Skinny's situation is similar. The beer bottle only becomes evidence when considered along with all (or most?) other non-black objects. Since no other facts were presented, Skinny loses.
Of course, this ignores all the evidence I've seen so far that indicates Skinny never loses. |
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cha
Daedalian Member
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Posted: Sun Nov 21, 2004 6:25 pm Post subject: 70 |
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| Forgot to log in above... |
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pob14
Daedalian Member
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Posted: Mon Nov 22, 2004 8:19 pm Post subject: 71 |
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I think the difficulty lies in a definitional problem.
The term "evidence" is a legal, and ordinary English, word with meaning that relates to those arenas. We use "evidence" in court to mean "anything that makes a disputed fact more or less likely to be true" (actually, that's the definition of RELEVANT evidence, but never mind for now).
However, the proposition (A>B)>(~B>~A) is one of formal logic. While formal logic is often useful in legal or everyday situations, it isn't the SAME. For example, we don't use the term "proof" in its formal sense in court. We don't, and can't, "prove" things in court the same way we prove them in symbolic logic.
So Skinny is mixing terms; he's offering inductive proof of a syllogistic proposition. And, though I'm not a logician nor a mathemetician, I think I can quote Hank Hill here: "That ain't right."
I think Skinny loses for cheating.
POB |
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Highest Prime
2^43112609 - 1
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Posted: Mon Nov 22, 2004 9:43 pm Post subject: 72 |
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| dave10000 wrote: |
| PLEASE address the fact that Skinny intentionally picked an object he knew not to be a raven -- he did *not* pick an object at random that had some chance of falsifying the claim. Since that is the case, what Skinny chose did NOT qualify as evidence. |
Your argument, taken as a whole, is certainly convincing, but I have difficulty accepting this as an absolute. If you don't mind, I'm curious what your verdict would be in the following situations:
(a) (The default scenario) You accept the bet and Skinny hands you a brown beer bottle, which he's set aside specifically for this bet (knowing it's a non-raven). (Not random; therefore not evidence. Correct?)
(b) You accept the bet and Skinny asks you to pick an item in the bar at random, knowing that there are no ravens in the bar.
(c) You accept the bet and Skinny asks you to pick an item at random from within a mile of where you're sitting, knowing that ravens are not indigenous to the area.
(d) Item selected as in (c), but Skinny knows that due to external factors (season, time of day, mating patterns of the local species of raven, etc.), the odds of a raven being in the area are far lower than they otherwise would be - perhaps 99.99% less than, or 90% less than, or 50% less than normal.
The crux of these questions being: At what point does the uncertainty (i.e. 'noise') inherent in Skinny's "certain knowledge" start interfering with the results of the experiment themselves and, therefore, render the "evidence" meaningless?
If you answered "no" to (b), for example, was this solely because Skinny "knows" there are no ravens in the bar (and so, by the reasoning provided, the evidence is not "random")? Perhaps one flew in through the back door five seconds ago. The odds of that are, of course, vanishingly small, but then again so is the degree of 'evidence' provided by the brown beer bottle in favor of the conclusion that "all non-black things are non-ravens."
I'm feeling increasingly quantum mechanical about this whole "evidence" discussion.
H' |
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dave10000
Tinhorn
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Posted: Mon Nov 22, 2004 10:53 pm Post subject: 73 |
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HP --
You certainly hit on the right line of reasoning in your post above. I agree that if it was unlikely but not impossible that the object chosen could be a raven, the object might still be viewed as "evidence" under an appropriately broad definition. (It would have a flaw upon a flaw, but that would still be nonzero which might be good enough for some definitions, though none that I personally would pick.)
The greater problem with Skinny's choice, I believe, is that -- as far as I can tell -- Skinny intentionally chose the brown bottle KNOWING it was not a raven. That is, he did not choose a non-black object at random to give to you, but rather chose a non-black object -- made sure it was not a raven -- and then gave it to you. That's not explicitly stated in the original puzzle, but in my view is a more reasonable interpretation of what Skinny did than assuming that he chose an item wholly at random from all non-black objects in the area. (I think Celt and I disagree on this, but I have no big quarrel if someone thinks Skinny *did* choose at random from objects in the bar. The original problem does not makes this clear.)
Thus, if I claimed that all 100 jelly beans in this jar were red and I pulled one out at random and it was red, that would be (slight) evidence supporting my claim. But if I looked in the bag and made sure the one I pulled out was red, that would not be any evidence at all supporting my claim. In my view, Skinny's bottle was more like the latter than the former, and thus in my view not evidence. For those who believe Skinny's bottle was more like the former, I have no problem with calling it "evidence" under a very broad interpretation of that word. The problem does not specify what "evidence" means, so that is another ambiguity leading to different possible results. Under most -- and perhaps all -- definitions that I would give to the word "evidence," the brown bottle would fail. But I recognize that under some sufficiently broad (and, in my view, philosophical and not particularly useful) definitions it could succeed. |
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dave10000
Tinhorn
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Posted: Mon Nov 22, 2004 11:11 pm Post subject: 74 |
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| Quote: |
| (d) Item selected as in (c), but Skinny knows that due to external factors (season, time of day, mating patterns of the local species of raven, etc.), the odds of a raven being in the area are far lower than they otherwise would be - perhaps 99.99% less than, or 90% less than, or 50% less than normal. |
I can model this, I think, with the jelly bean example. 100 jelly beans in the bag. I throw a die -- unseen by you -- and if it is a 6 I pull a bean at random, otherwise I pull a bean known to me to be red.
If I go through this procedure and show you a red bean, does that support the proposition that "all beans in the bag are red"?
In my view, this requires one to define "support the proposition" -- or "evidence" if you want to use that word. I believe that a *court* would not accept this as evidence, since there is a 5/6 chance that the item offered is not relevant. I recorgnize that one could look at it differently and say that, overall, it is evidence, but 5/6 weaker than if it had been pulled at random. But that's not how a court would look at it. The court generally slices questions up individually, and since there is a 5/6 chance it's not relevant, the court would reject it as evidence. If you have a definition of evidence that this fits, fine. All that shows is that "evidence" can reasonably mean more than one thing.
To see another way that probabilities get screwy in court, consider the following:
Suppose in a trial Mr. X hit someone else's car if and only if items A, B, and C are true. If the court asked the jury the three questions:
Is A true?
Is B true?
Is C true?
and if the jury (assume everyone is like-minded) though that each of the answers had a .6 probability of being true. You answer a question "yes" if you think it is more likely to be true than not true. The jury would answer each question "yes" and the veridct would be that Mr. X was responsible.
However, suppose the question was:
Are A, B, and C all true?
Now, a smart jury (hah!) would see that the answer to THIS question is NO, because .6 * .6 * .6 < .5, and you need a truth value of at least .5 to answer yes to a question.
Although the results should not be different as a matter of logic, they are different as a matter of how the question was put to the jury. Thus, small differences in interpretation can lead to drastic differences in result. It should not be surprising, therefore, that small differences to the question "what do you mean by "evidence"? can lead to different results in situations designed to test the margins. |
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Rio
Guest
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Posted: Tue Nov 23, 2004 12:49 am Post subject: 75 |
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Dave10K:
The jelly bean example is nice, and while I recognize that you've moved from "Nevermore" on to an interesting discussion of the relationship between probability and evidence, I'd like to pose the following for your consideration:
B1: "All beans in the bag are red"
is equivalent to
R1: "all ravens (in the world) are black"
except that you've nicely shrunk the world down to the size of the bag. The most straightforward contrapositive of B1 is:
B2: "all non-red things in the bag are non-beans."
Let's assume for simplicity's sake that there are some beans in the bag, as well as some non-red things, but that beyond that, you have no knowledge of what's in the bag. (Nothing hinges on this assumption - it's just easier to talk about.)
If Skinny reaches into the bag and pulls out a silver coin, he has demonstrated something from the bag that is non-red and a non-bean, satisfying B2. But my question for you is this: has the production of the coin given you any more reason to believe that all beans in the bag are red than you had before the coin was produced, whether or not the coin was grabbed at random or intentionally?
In other words, how does the production of the coin help you decide whether B1 is more likely to be true or false?
From my perspective, it doesn't, because the production of the coin cannot, even probabilistically, distinguish between the case where all beans in the bag are red, and the case where none of them are.
On a completely different note, one could also make the following independent argument:
Evidence, whatever that is, is non-transitive. That is, if information I is evidence for proposition P, and P entails Q, I does not thereby become evidence for Q. Why? Well assume it were transitive. Then, since any arbitrary proposition entails a true proposition, it follows that , e.g., fossils, which surely constitute evidence for something, constitute evidence for the claim my computer has more RAM now than it did 3 years ago, which is absurd. Therefore, we must reject the hypothesis that the evidentiary relationship is transitive.
Note that Skinny's claim cannot be made unless evidence is transitive. Since it is not. Skinny's out of luck.
What do you think? |
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dave10000
Tinhorn
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Posted: Tue Nov 23, 2004 2:02 am Post subject: 76 |
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| Quote: |
| In other words, how does the production of the coin help you decide whether B1 is more likely to be true or false? |
Yes, odd, but that's why the raven "paradox" has gotten a lot of mileage.
I basically answered the question in Post 48:
| Quote: |
| The question is, then, if I showed you 99% of all non-black objects in the universe would you feel pretty good about the statement "all Glurtzes are black"? 99.99999% of all non-black objects? All non-black objects in the universe except one? Surely you'd admit (wouldn't you?) that if I randomly showed you all non-black objects in the universe except one, and they were all non-Glurtzes, you'd feel pretty good that the final one was a non-Glurtz, too. But if that's the case, you should feel pretty good that all Glurtzes were black. The question is, then, what percentage of non-black objects do you need to see to feel pretty good about the statement "all non-black objects are non-Glurtzes." And, doesn't every non-black non-Glurtz you see up until that point contribute a bit to that feeling? If not, don't you concede that, at some point along the line, a non-black non-Glurtz tips the balance from you not feeling pretty good to you feeling pretty good? And thus, doesn't that same non-black non-Glurtz do the same thing about your belief in the statement "all Glurtzes are black"? |
The bag experiment is not simply another way of "looking at it," but rather it makes the problem more specific. It is important that the non-black object be chosen in a way that a priori had some chance of including a disconfirming instance *if* it existed. That's why "hey, there's a brown bottle" does not do it for me. But if there are N non-red objects in the bag, and you show me N-1, I feel pretty good about "all jelly beans in the bag are red." And so, even if I do not know how large N is, I know that each one -- if randomly chosen -- gets me closer to N.
Note that HP's Post 72 is on the money -- by "random" I do not mean that every object has to have an equal probability. But I do mean that the method of choice has to include some sufficient probability of a disconfirming item to be selected if it exists, and the lesser the probability, the weaker the evidence. (e.g, If I pick randomly from 100000 non-black objects in a bar, where there is only a 1/1000000000 chance that a raven is in the bar, that is "less evidence" than if I picked randomly from 100000 non-black objects at a zoo.)
And again, I think the "paradox" here is helped along by two different definitions of "evidence." No one would change their belief in "all ravens are black" based upon a brown bottle, even if randomly picked (one definition of evidence), but as a matter of pure logic, it may "help confirm" the proposition (another possible definition of evidence).
Perhaps this is so because our "belief" is subject to error bars -- Maybe my belief of "all ravens are black" is 85.73%, with a margin of error (or fuzziness) of 1%. On different days you might get slightly different answers from me as to the strength of my belief, even though the strength hasn't changed at all. The quantum of evidence that a bron bottle represents is so tiny, that it falls well within the margin of error and does not even come close to actually affecting our belief. We need something more substantial to count as "belief-affecting evidence," and the fact that we use the word "evidence" to mean both "belief-affecting evidence" and "purely logical-conclusion evidence" is what poses the problem. If we called one "flerg" and the other "glip", the raven "paradox" would probably disappear. (Bolded because I like the way that came out.) |
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Rio
Guest
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Posted: Tue Nov 23, 2004 4:40 am Post subject: 77 |
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| Quote: |
| But if there are N non-red objects in the bag, and you show me N-1, I feel pretty good about "all jelly beans in the bag are red." And so, even if I do not know how large N is, I know that each one -- if randomly chosen -- gets me closer to N. |
I have to disagree. The fact is that there might be no beans in the bag at all, let alone any red ones. Removing and displaying every non-red item in the bag doesn't get you any closer to determining that fact, assuming there are also a reasonable number of red non-beans in the bag (so it doesn't become empty). In other words, showing you every non-red thing in the bag doesn't allow you to distinguish between "all beans in the bag are red" and "no beans in the bag are red". All you can conclude are that there are no non-red beans in the bag, which is not the same. The point is that by removing and displaying every non-red item in the bag, while you may be able to definitively establish that "all non-red items are non-beans," you cannot establish, even marginally, that all beans in the bag are red. Why? Because the proposition that "all beans in the bag are red" requires different evidence than the proposition that all non-red things in the bag are non-beans.
The more I think about it, the more I think the Nevermore case breaks down because of the transitivity issue I mentioned in the last post. Skinny states that P --> Q, and asserts something as evidence for P, concluding therefore that it is thus also evidence for Q. But if this principle held, it would follow that any contigent fact or state of affairs would constitute evidence for any other, since Q --> (P--> Q) is demonstrably true under first -order propsitional logic. In other words, e.g., that you post under the moniker "dave10000" would constitute evidence for the proposition that I am now eating an orange (because in fact I am).
Since this is clearly so far removed from anything anyone would call "evidence", and since it appears to be the key step in Skinny's argument, I don't see how we can conclude anything except that Skinny's logic is flawed, the bottle, while it may constitute weak inductive evidence for the claim that all non-black things are non-ravens, cannot simply in virtue of that constitute evidence regarding the proposition that all ravens are black.[/b] |
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dave10000
Tinhorn
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Posted: Tue Nov 23, 2004 6:02 am Post subject: 78 |
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| Quote: |
| The fact is that there might be no beans in the bag at all, let alone any red ones. Removing and displaying every non-red item in the bag doesn't get you any closer to determining that fact, assuming there are also a reasonable number of red non-beans in the bag (so it doesn't become empty). In other words, showing you every non-red thing in the bag doesn't allow you to distinguish between "all beans in the bag are red" and "no beans in the bag are red". |
By the standard rules of logic, "all beans in the bag are red" is true if there are no red beans in the bag. If you disagree because it doesn't seem satisfying to you, that's your prerogative, but then you're operating under a nonstandard set of rules (or at least nonstandard as far as logic goes). |
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LoudmouthLee
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Posted: Wed Nov 24, 2004 5:31 am Post subject: 79 |
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New here, but as a Philosophy minor (and as an English Teacher), I feel I can shed some light onto this issue.
This issue is a famous logical fallacy called "Hasty Generalization"... Here's another example:
(1) LoudmouthLee, the New Yorker, stole my wallet. Therefore, all New Yorkers are theives.
(You, obviously cannot say that...)
or:
(2) I asked six of my friends what they thought of the new government restraints and they agreed it is a good idea. The new restraints are therefore generally popular.
(Too small of a sample, right?)
Someone who is more in-tune with their mathematics (unlike me) can write a fromal mathematical prrof when it comes to probability theory. I'll just leave you guys to it.
Hope this helps, if you need more info about the logical fallacy, I'll be happy to post.
Best regards,
Lee D. |
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Guest
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Posted: Wed Nov 24, 2004 5:49 am Post subject: 80 |
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1: All ravens are black ==> According to Skinny
2: All non black are non-ravens ==> Based First Statement
3: Something is non black only prove that Something is not raven since all ravens are black, according to the first statement. Afterall the first statement is the FACT we used in the puzzle, to prove other statement.
4. Now assume the bottle is black. Is it prove that the bottle is raven? No. Because we need the statement of "ALL BLACK IS RAVEN".
So, Skinny lost because he simply didn't prove all ravens are black from the bottle. |
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