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 Discuss Skunked Again here Goto page 1, 2  Next
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MatthewV
Daedalian Member :_

 Posted: Sun May 29, 2005 7:14 am    Post subject: 1 Link to Puzzle
Aalk4308
Daedalian Member

 Posted: Sun May 29, 2005 3:06 pm    Post subject: 2 Some initial thoughts: All of the cards are red (either hearts or diamonds). Skunks #1 and #5 both have 2d and 3h, but otherwise the skunks do not share any cards. We are not told the set of rules by which the skunks move. I guess the point of the puzzle is to determine what the rules are so that Betty can have a winning betting strategy. Some possibilites: If a skunk's card is chosen, it moves a fixed distance If a skunk's card is chosen, it moves a distance based on the card's rank or suit For each card a skunk holds matching the chosen card's suit or rank, it moves some distance. For each card a skunk holds that matches neither the rank or suit of the chosen card, it moves some distance. The story says that when a card is drawn, each skunk moves a certain distance and then stops. This might mean that all skunks move at least x units after each draw, regardless of the card. The rules might also have skunks to move backwards as well as forwards. We are not told if the cards are replaced into the deck after being drawn.
dave10000
Tinhorn

Posted: Sun May 29, 2005 3:56 pm    Post subject: 3

 Quote: We are not told the set of rules by which the skunks move. I guess the point of the puzzle is to determine what the rules are so that Betty can have a winning betting strategy.

If that is in fact the point (and it seems to be), then there is no unique answer. For example, Betty's observations of the race she saw may have been:

- Any skunk that does not have the Kh moves 1-5 spaces per turn, whereas any skunk that does have the Kh moves 6-10 spaces per turn.

If she observed that, and if that rule holds for this race, then Skunk 4 will clearly win. But of course if Betty's observation had revealed this about a different card, then a different skunk would win.

(Or, perhaps Betty observed that Skunk 3 (or perhaps a skunk with the 9d) always moves the sum of the other skunks, which would make Skunk 3 the favorite.)

Thus, rules could be determined, consistent with the statement of the problem, that would allow Betty's choice to be any of the skunks. It does not seem that a unique solution is possible.
Tahnan
Daedalian Member

 Posted: Sun May 29, 2005 4:56 pm    Post subject: 4 Dave is of course right. Nevertheless, I think we can infer, based on the word "skunk" and the fact that the track is 121 units long, exactly what mechanism is being used to move the skunks forward. (Hint: it ain't poker.)
Tahnan
Daedalian Member

Posted: Sun May 29, 2005 4:57 pm    Post subject: 5

--though actually, in a sense,

 dave10000 wrote: For example, Betty's observations of the race she saw may have been: - Any skunk that does not have the Kh moves 1-5 spaces per turn, whereas any skunk that does have the Kh moves 6-10 spaces per turn.

That isn't consistent with what we've been told. Skinny Dakota would never use anything that a casual observer could pick up so easily!
Tony Gardner
Daedalian Member

 Posted: Sun May 29, 2005 5:01 pm    Post subject: 6 I know what game you mean Tahnan (easily found with Google), but I don't know how to play the game. If anyone around here does, that would probably greatly simplify the task at hand.
OcularGold
Daedalian Member

 Posted: Sun May 29, 2005 6:16 pm    Post subject: 7 I havent done any of the math yet, but I would put my money on 4. this should help.
mathgrant
A very tilted cell member

 Posted: Sun May 29, 2005 6:18 pm    Post subject: 8 I would never have figured out the rule without the knowledge that 121 spaces is significant, and that it's based on a game. Nevertheless, I suck at CRIBBAGE, so I certainly shan't analyze it. _________________My logic puzzle blog
Ctorj
Did I spell that right?

Posted: Sun May 29, 2005 7:43 pm    Post subject: 9

 Quote: Dave is of course right. Nevertheless, I think we can infer, based on the word "skunk" and the fact that the track is 121 units long, exactly what mechanism is being used to move the skunks forward. (Hint: it ain't poker.)

 Quote: havent done any of the math yet, but I would put my money on 4. this should help.

Wouldn't this rule out Cribbage? I can see how cribbage can be a poker game. This being the case, the solution may be something completely different. I googled poker and cribbage and they seem to be associated though I don't know for sure. I do not play cribbage.
Tahnan
Daedalian Member

Posted: Sun May 29, 2005 7:44 pm    Post subject: 10

So here's my analysis. Setting aside questions of suit,

 Code: A  2  3  4  5  6  7  8  9 10  J  Q  K 1 10 10 10 10  7  6  6  8  8  8  8  8  8 8.230769 2  4  8  9 16 14 14 12  9  8  8  8  8  8 9.692308 3 10 10  8  8  9 16 16 16 16  9  8  8  8 10.92308 4  8  8  8  8 16  8  8  8  8 10 15 16 16 10.53846 5 16  4  4 16  6  4  8  8  6 12 12 12 12 9.230769

The first column is the skunk number; the columns headed by cards indicate the value of the skunks' hands with that card added. The final column represents the expected value per hand.

But! One skunk has two jacks. That means that, half the time (on a red card), that skunk gets an extra point for the jack matching the suit of the card that turns up. Therefore, skunk #4 has an extra .5 expected points per hand. That slight difference pushes #4 into the expected lead.

Assuming, that is, that it really is cribbage based and not, as Dave10000 suggests, any other arbitrary method; assuming the director is using a full 52-card deck regardless of the cards printed on the skunks' outfits; and assuming the director shuffles his card back in each time.
dave10000
Tinhorn

Posted: Sun May 29, 2005 10:04 pm    Post subject: 11

 Quote: That isn't consistent with what we've been told. Skinny Dakota would never use anything that a casual observer could pick up so easily!

Well, a couple of things. Skinny would never use something that would allow an observer to win at all. Much more consistent with Skinny is to set up the first race to *look* like cribbage, thus getting people like Betty to bet the farm on the second race, only to have the rule be something else.

Also, keep in mind, we weren't told that this a race run by "Harold the Hinter," who likes to drop subtle hints to the race rules and doesn't mind paying off to those smart enough to figure them out. (Under that scenario, I'd buy the cribbage angle.) Rather, we were told this a race run by Skinny, so there's no implication that the hints lead to the right result -- to the contrary, there's more of an implication that the hints lead to the wrong result.

Finally, I don't see how we can square:
 Quote: Betty was positive she was about to make a small fortune

with the cribbage scenario. In the cribbage scenario, it seems only like one horse is more likely to win than any other skunk is, not that anyone would be "positive" that the skunk would win (unless I am missing something about how the cribbage scenario works). Since the skunks are each going off at 15 to 2, the only way to be "positive" of winning a small fortune under the cribbage scenario is to bet on all the skunks. By betting \$2 on each skunk (a total of \$10) you'd get \$17 back, for a 70% return on your investment. That seems like a much surer bet with Skinny at the booth than betting the cribbage angle (which could lose by bad luck *or* if Skinny wasn't being straightforward -- the latter of which is almost certainly the case).

Aside: Even with this "sure thing," I would not bet, under my long-standing rule that you should never accept any bet Skinny offers, because there's always a catch. (For example, when you win your \$2 bet, Skinny pays you 15 *yen*, stating that by 15 to 2 he meant 15 yen to 2 dollars.)
Tahnan
Daedalian Member

Posted: Mon May 30, 2005 3:35 am    Post subject: 12

dave10000 wrote:
 Quote: That isn't consistent with what we've been told. Skinny Dakota would never use anything that a casual observer could pick up so easily!

Well, a couple of things. Skinny would never use something that would allow an observer to win at all....

Yeah, I know. I was being mostly facetious on that.

dave10001 wrote:
Finally, I don't see how we can square:
 Quote: Betty was positive she was about to make a small fortune

with the cribbage scenario. In the cribbage scenario, it seems only like one horse is more likely to win than any other skunk is, not that anyone would be "positive" that the skunk would win (unless I am missing something about how the cribbage scenario works).

That did occur to me, actually, and I meant to throw in an offhand comment in my post, to the effect that this race is not likely to be a blowout by any means, and that indeed I'd be surprised if any of the skunks were skunked.
Jedo the Jedi
Paragon in Training

 Posted: Mon May 30, 2005 4:51 am    Post subject: 13 I would put my money on skunk 3 because regardless of the card drawn, it will always move forward at least 8, assuming the cribbage scenario. It's chances are greatly increased when one of those cards is duplicated. I believe that that hand produces the highest possible payoff in cribbage. Of course, if skunk 4 got lucky with the fives, it would win quite easily. Yeah, what Tahnan said with the statistics. As for the bit about Skinny Dakota running the races, I don't really put much stock in that changing things. True, there will most likely be a twist of some sort, but not so much that it changes the fact that this is modeled after cribbage. I think that cribbage itself is rather obscure, so that could be part of his money-making plot._________________Paragon Tally: 18 mafia, 3 SKs (1 twice), 1 cultist, numerous chat scum...and counting.
Daedalian Member

 Posted: Mon May 30, 2005 8:32 am    Post subject: 14 I also don't think the 15 to 2 odds are significant except as another hint towards cribbage (where you peg 2 points for making the total 15 on the play, or a group of cards that total 15 in your hand for the show).
dave10000
Tinhorn

 Posted: Mon May 30, 2005 6:53 pm    Post subject: 15 Another thought -- Why are we to assume that the race director is holding up a card randomly chosen from a *full* deck? Isn't it at least as logical -- if not more logical -- that the card would be chosen from a deck in which the cards appearing on the skunks had been removed? (Otherwise the scoring card could be a duplicate of one of the hand cards, which I believe is not possible in cribbage.) If the deck used is such a "reduced" deck (which, again, seems *at least* as likely as using a full deck), doesn't that change the result?
Aalk4308
Daedalian Member

Posted: Mon May 30, 2005 8:22 pm    Post subject: 16

 dave10000 wrote: Another thought -- Why are we to assume that the race director is holding up a card randomly chosen from a *full* deck? Isn't it at least as logical -- if not more logical -- that the card would be chosen from a deck in which the cards appearing on the skunks had been removed?

That would be logical. But on the other hand, skunks #1 and #5 both have the 2d and 3h, which couldn't happen in a real game (with one deck). Then again, cribbage isn't a five-person game, so anything is possible.

Also, here are two minor corrections to the scoring grid Tahnan provided. Skunk #2 scores 6 with an Ace drawn (run of four plus a 15). Skunk #5 scores 8 with a two or three drawn (three of a kind plus a pair).
dave10000
Tinhorn

 Posted: Mon May 30, 2005 9:56 pm    Post subject: 17 I still don't see the answer even assuming that the cribbage angle is correct. It is simply not the case that the skunk with the highest average per turn is necessarily the most likely to win the race. For example, a skunk that moved 120 spaces for any ace or the Jack of Hearts, but zero for all other cards, would take on average around 17 cards to cross the finish line, and thus on average would be beaten by each of the other skunks, even though our new skunk had an average move of more than 11 spaces per card, better than any of the skunks currently in the race. Moreover, even if a skunk might be better head-to-head than any of the others, that does not mean he has a good chance of winning in the field of all other skunks. Consider a hold'em poker hand of 7-7, which is a favorite to beat any of the following in a 1-on-1 match: A-8, K-9, Q-T. But it has almost no chance of winning if ALL of those hands are against it at the same time. Similarly, showing that Skunk 4 has the greatest average move-per-card does not establish that it is the Skunk with the greatest chance of winning the race. More work needs to be done. Consider, for example, a skunk running against 4 other skunks each of which moved 1 space more per card than that skunk *except* that one of their highest scores was changed to a zero -- with this happening for a different card for each skunk. For example: Skunk 14 = 14 14 14 14 14 14 . . . other skunks = 0 15 15 15 15 15 . . . 15 0 15 15 15 15 . . . 15 15 0 15 15 15 . . . 15 15 15 0 15 15 . . . Skunk 14 would have a better spaces-per-average than any of the other skunks, but would have a lesser chance of winning than any of the other skunks. It could not win any race unless an A, 2, 3, *and* 4 came up in the first 9 cards. The situation in the original puzzle is not so drastic, and it may well be that there the skunk with the greatest number of spaces per card *is* the best one to bet on, but this shows that one cannot simply say "most spaces per card" and end the analysis. SIMULATION TIME For those interested in what a simulation shows, here are the results: 1= 0.0% 2 = 4.1% 3 = 42.2% 4 = 44.1% 5 = 9.6% Given that Betty has a less than 50% chance of winning at all, I don't see how the cribbage answer is consistent with the puzzle language that "After pondering at the board for a few minutes, Betty was positive she was about to make a small fortune . . ." Unless we are supposed to disregard Betty's "positiveness" as a mere statement of her mindset that did not reflect reality -- but if that's true, then there's no way we could hope to answer the question correctly, since she might have bet on *any* skunk having a positive (but wrong) mindset. Certainly her positive mindset was wrong (by about 56%) with respect to Skunk 4.
dave10000
Tinhorn

 Posted: Mon May 30, 2005 10:45 pm    Post subject: 18 Follow-up: To make the point in my previous post more specific, suppose that we change Skunk 5 from: 16 8 8 16 6 4 8 8 6 12 12 12 12 -- 9.846 TO 8 8 12 12 12 4 8 8 6 16 16 12 12 -- 10.307 Then Skunk 4 still has the best "spaces per move" number, BUT the simulation shows: 1 = 0% 2 = 4.0% 3 = 42.5% 4 = 41.1% 5 = 12.4% Basically, the slight improvement of Skunk 5 took away from Skunk 4 rather than Skunk 3 (intentionally so). So now, Skunk 3 has the best chance of winning in this field. But this field looks awfully similar to the previous field, and Skunk 4 still has the best "spaces per move" score. The question is, then, how did Betty know merely from looking at the scores that Skunk 4 was the one to bet on in the previous scenario. It could not have been from looking at the "spaces per move" alone. Did she run a simulation? Is that what we are supposed to assume? The original puzzle says that she was ready to bet "[a]fter watching for a few more minutes . . . ," which does not sound like she had time for, or that she in fact ran, a simulation. Hopefully the official answer will shed light on some of these issues.
Jedo the Jedi
Paragon in Training

 Posted: Tue May 31, 2005 1:09 am    Post subject: 19 Dang it, Dave! Your post was too long and I forgot my idea about the puzzle. Something you said made me have an epiphany and by the time I went and looked at the puzzle, I had forgotten it! I'll have to come back to this I guess._________________Paragon Tally: 18 mafia, 3 SKs (1 twice), 1 cultist, numerous chat scum...and counting.
ralphmerridew
Daedalian Member

Posted: Wed Jun 08, 2005 12:05 am    Post subject: 20

 dave10000 wrote: Consider, for example, a skunk running against 4 other skunks each of which moved 1 space more per card than that skunk *except* that one of their highest scores was changed to a zero -- with this happening for a different card for each skunk. For example: Skunk 14 = 14 14 14 14 14 14 . . . other skunks = 0 15 15 15 15 15 . . . 15 0 15 15 15 15 . . . 15 15 0 15 15 15 . . . 15 15 15 0 15 15 . . . Skunk 14 would have a better spaces-per-average than any of the other skunks,

I get that skunk14 moves 14 spaces per card, and the others get, on average, 15 * (51/52) == 14.7 spaces per card.

I also believe that, as the race gets longer, the probability of (skunk with highest per-card average wins) approaches 1, and if there is a tie for highest per-card average, then P(any particular such skunk wins) approaches 1/(#such skunks).
Tahnan
Daedalian Member

Posted: Wed Jun 08, 2005 4:02 am    Post subject: 21

 dave10000 wrote: I still don't see the answer even assuming that the cribbage angle is correct. It is simply not the case that the skunk with the highest average per turn is necessarily the most likely to win the race....

This occurred to me. I decided I was more interested in working out the cribbage aspect than in working out the actual probability. :-) I did give a cursory--not a scientific--glance over the data to see if there was likely to be the sort of situation Dave describes, in which the skunk with the technically higher average-moves-per-turn would only win in certain fortunate circumstances; I didn't see one.

And, as I said (didn't I?), I realized that Betty's certainty was somewhat unwarranted. Ah well.
dave10000
Tinhorn

Posted: Wed Jun 08, 2005 5:29 am    Post subject: 22

 Quote: I get that skunk14 moves 14 spaces per card, and the others get, on average, 15 * (51/52) == 14.7 spaces per card.

ralphmerridew -- consistent with earlier usage, each 0 represents 4 cards (all the aces, or all the twos, etc.) Thus, the other skunks move, on average, 15*(12/13) = 13.8 spaces per card. But that may have not been sufficiently clear in my previous post.

Other than that . . . yeah, what Tahnan said.
Zeke Hoskin
Guest

 Posted: Wed Jun 08, 2005 7:40 pm    Post subject: 23 There is something fishy in the game description. Fifteen-two odds on each of five racers? Put a hundred on each. The winner earns seven hundred and fifty, plus that hundred back, net payoff three hundred and fifty. The only way Skinny can win is if the race never ends
bobandyo
Guest

 Posted: Fri Jun 10, 2005 1:35 pm    Post subject: 24 Keep in mind - that in this race as in real cribbage, its the 1st racer to reach 121 that wins. It does not require a complete turn to transpire and all skunks to move their allotted share of moves. In all liklihood this will be a close race as it comes down to the finish line. Skinny could control the winner by determining which skunk pegs 1st on the final card.
Guest

Posted: Tue Jun 14, 2005 3:13 am    Post subject: 25

 bobandyo wrote: Keep in mind - that in this race as in real cribbage, its the 1st racer to reach 121 that wins. It does not require a complete turn to transpire and all skunks to move their allotted share of moves. In all liklihood this will be a close race as it comes down to the finish line. Skinny could control the winner by determining which skunk pegs 1st on the final card.
Arkive
Icarian Member

 Posted: Tue Jun 21, 2005 5:19 pm    Post subject: 26 Well, the 15-2 odds is clearly either misleading, or the rules to the race itself are. The rules don't specify whether the skunks move in turns, or in unison, so if more then one skunk has a high enough score to cross the finish line on that go, the race would end in a tie. Since the rules state that, "The first skunk to complete the track wins the race", then regardless of who you bet on, even if it was all of them, you could theoretically lose money. Now I don't know what the odds of one skunk clearly winning is, but someone's previous numbers do show that the average points/turn is fairly close so I would guess there is a good chance that Skinny would win money overall. The only problem I have is that the puzzle gives the impression that from what she observed, she clearly thought one of the skunks would win based on his cards, so I'm not sure if my theory holds any water then.
Holywhippet
Guest

 Posted: Thu Jun 23, 2005 5:11 am    Post subject: 27 Rules on five card Cribbage can be found here: http://www.pagat.com/adders/cribbage.html These analysis seems correct, but as people have said, it doesn't seem to offer much of a guarantee. Skunks 3 and 4 don't have that much between them under the rules suggested so I wouldn't feel either of them to be a certainty. Since Betty is putting everything into one bet there must be some other set of rules being used. For that matter, there's also the question of what "completing" the track means. If the track is circular with 121 units, a skunk might need to visit every single unit before they win - even though that means several laps. The other odd thing is that the track is 121 units long. Five card cribbage is first to 61 points. Let me try a poker analysis with the hand rankings (found here: http://www.pagat.com/vying/pokerrank.html) being used to determine distance. Assuming pair is one movement and royal flush is 9: Card A 2 3 4 5 6 7 8 9 10 J Q K S 1 1 1 1 1 4 0 0 0 0 0 0 0 0 K 2 0 0 4 1 1 1 1 4 0 0 0 0 0 U 3 0 0 0 4 1 1 1 1 4 0 0 0 0 N 4 1 1 1 1 1 1 1 1 1 1 3 2 2 K 5 2 6 6 2 2 2 2 2 2 2 2 2 2 Under these conditions, skunk 5 is going to rocket to the finish line. BTW, if I'm wrong, I wonder why the cards on the skunks are only diamonds or hearts - not clubs or spades?
Arkive
Icarian Member

 Posted: Thu Jun 23, 2005 1:23 pm    Post subject: 28 Holywhippit: 5 card cribbage is considered the older style game, with 6 card replacing it as the more common variation (at least in terms of 2 players). Also, while some of the older boards may have 60 holes, it's usually two laps around the board for a score of 121 or higher to win the game. However, your poker logic might be along the lines of what she was thinking, which would explain why she was so confident that a skunk (in this case, #5) would win the race.
Guest

Posted: Thu Jun 23, 2005 9:35 pm    Post subject: 29

 Arkive wrote: Holywhippit: 5 card cribbage is considered the older style game, with 6 card replacing it as the more common variation (at least in terms of 2 players). Also, while some of the older boards may have 60 holes, it's usually two laps around the board for a score of 121 or higher to win the game. However, your poker logic might be along the lines of what she was thinking, which would explain why she was so confident that a skunk (in this case, #5) would win the race.

I know 5 card is the older style, but since the skunks have 4 cards and another card is held up, that only makes 5 cards. Admittedly I didn't read up on the six card version rules but I assume it does in fact use six cards.

As you say, the poker explanation makes more sense since it gives much better odds for a particular winner. The clues all point to cribbage but the odds just don't make sense for her to put it all on one bet.
bobandyo
Daedalian Member

 Posted: Thu Jun 23, 2005 10:35 pm    Post subject: 30 6-card cribbage is the 2-player game. 5-card cribbage is the 4-person game (at least as I play it) and I always play to 121.
Lucky Wizard
Daedalian Member

 Posted: Fri Jun 24, 2005 5:31 am    Post subject: 31 It probably doesn't really matter whether it's five-card or six-card -- according to http://en.wikipedia.org/wiki/Cribbage , either way you still end up with 4 cards plus the turn-up card at the end. Not that I have any idea on the puzzle other than what's been suggested.
MatthewV
Daedalian Member :_

 Posted: Fri Jun 24, 2005 7:24 am    Post subject: 32 Cribbage with three people is played by dealing each person five cards and one to the crib; all players add just one card.
LoudmouthLee
Member of the Year

 Posted: Fri Jun 24, 2005 6:14 pm    Post subject: 33 15 to 2 could just be a cribbage hint, eh? _________________-LmL I'm sorry. I have no desire to talk to you.
dave10000
Tinhorn

Posted: Fri Jun 24, 2005 10:27 pm    Post subject: 34

 Quote: 15 to 2 could just be a cribbage hint, eh?

But remember the track is run by Skinny Dakota. It is far more likely that he would set the odds to try to mislead than that he would set them to try to help. He would say that any incorrect assumptions you drew were your own fault. If the 15-2 odds were supposed to be a hint, then the poser of the problem should not have had the track run by Skinny Dakota, who is a notorious misleader.

In any event, this puzzle seems to have run its course. Official answer, please?
Guest

 Posted: Sat Jun 25, 2005 12:37 am    Post subject: 35 If indeed the poker analysis presents such a clear winner and the cribbage analysis offers no real advantage at all, then I would assume this is the best solution offered thus far. Any chance the owner of this puzzle could give us a yay or nay?...or least offer a friendly hint otherwise?
warpdragon
Daedalian Member

 Posted: Sun Jun 26, 2005 2:54 am    Post subject: 36 I think the fact that that there are only two suits may lead to the idea that the deck is not a standard deck. Wikipedia says the disambiguation of skunk is equivalent to a total victory or a shutout. http://en.wikipedia.org/wiki/Skunk_%28disambiguation%29 This may imply that if looked at hard enough there is a clear cut winner.
L'lanmal
Daedalian Member

Posted: Sun Jun 26, 2005 8:22 pm    Post subject: 37

 Lucky Wizard wrote: It probably doesn't really matter whether it's five-card or six-card -- according to http://en.wikipedia.org/wiki/Cribbage , either way you still end up with 4 cards plus the turn-up card at the end.

You misread this. It says in five-card cribbage you end up with 3 cards in your hand (plus the one cut).

You do, however, end up with four in the crib, just as in modern cribbage.

 http://en.wikipedia.org/wiki/Cribbage wrote: Five-card cribbage (for two players) is the oldest version, and is sometimes known as "old game". Each player is dealt five cards, so the crib consists of four cards but each hand only three.

I scanned the posts and didn't see this mentioned, so will say it for those who don't know how to play cribbage. Apologies if someone explained it before.

To be skunked in cribbage means that you have fewer than 91 points when your opponents go out. On a 120-hole (usually circular) cribbage board, this is marked by a line called the "skunk line". On a 60-hole straight cribbage board, this is where you would turn for the third time.

An optional rule in a standard match of cribbage is that skunking your opponent counts as two wins, rather than one. So being skunked is something to really avoid in a three-game match.

To fail to get 61 points is to be "double-skunked". This isn't as standard a term, but is fairly common usage. Some players count a double-skunking as either 3 or 4 wins, though many don't.

The only way I can make sense of the 15-2 odds is that you are supposed to be betting on which skunk gets skunked. In this case, there is not always going to be a "winner", so you can't guarantee winning by betting on all skunks.
ralphmerridew
Daedalian Member

 Posted: Mon Jun 27, 2005 4:39 pm    Post subject: 38 Holywhippet: Your post will look better if you put the table within CODE tags.
Holywhippet
Guest

Posted: Wed Jun 29, 2005 5:31 am    Post subject: 39

 ralphmerridew wrote: Holywhippet: Your post will look better if you put the table within CODE tags.

Ok. Here.
Card
 Code: A 2 3 4 5 6 7 8 9 10 J Q K S 1 1 1 1 1 4 0 0 0 0 0 0 0 0 K 2 0 0 4 1 1 1 1 4 0 0 0 0 0 U 3 0 0 0 4 1 1 1 1 4 0 0 0 0 N 4 1 1 1 1 1 1 1 1 1 1 3 2 2 K 5 2 6 6 2 2 2 2 2 2 2 2 2 2
[/code]
Thok
Guest

 Posted: Sat Jul 02, 2005 9:05 am    Post subject: 40 Random thought-maybe only part of the cribbage game is implemented? In particular, if you only do the cut, hand 4 has an extremely dominant advantage (scores 1 point on any red card, every other skunk needs a jack to get points).
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