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Samadhi's school help thread
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Lepton*
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PostPosted: Fri Mar 24, 2006 1:31 am    Post subject: 81 Reply with quote

I think that the best exams are overly long, homogeneous, comprehensive, and challenging. It forces the students to prove their knowledge. The GREs subject tests are written such that if you can correctly answer half of the questions, then you will have a very favourable score.

I wrote a stupid 20-minute exam (in a 1.5 hour period) today. I didn't feel like I was able to demonstrate my knowledge. I feel that I have demonstrated my knowledge after writing prize exams (Putnam, etc).

Education research, if I remember correctly, identifies a number of different levels of comprehension. Here is an overview. In essence, one should learn up to the ability to synthesize and critically evaluate similar arguments. In math, this could mean being able to construct a prove using previously-learned techniques (without having seen this particular proof before) and seeing where a faulty proof might break down. Almost nobody tests for these things because such questions are Hard and people complain. Thus we have a status quo where university examinations don't even test for what they should be testing for.
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CzarJ
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PostPosted: Fri Mar 24, 2006 3:54 am    Post subject: 82 Reply with quote

Ooh, the Putnam was fun.

I'm pretty sure I got a zero, but it was fun.
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casinopete
Emergency Backup Antrax



PostPosted: Fri Mar 24, 2006 4:02 am    Post subject: 83 Reply with quote

I've experienced the Hard Test in a hardware class. I got a 36, and was absolutely mortified until it became clear that it scored a B+.

(This class was 15hrs+/week of work, despite being 4 credits)
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Samadhi
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PostPosted: Fri Mar 24, 2006 6:57 am    Post subject: 84 Reply with quote

Tests came back today. I tied for second highest. A 75 of 100. All but 12 lost points were from mistakes that I really shouldn't have made. 6 points were from not determining whether the function was differentiable, the other 6 points I'm pissed about.

The question was 'Let a = <2,1,3>, b = <1,3,5>, c = <1,0,6>; Are these vectors coplanar?'

I wrote:
Code:

    2 1 3
    1 3 5
det 1 0 6

= 36 + (-1) + (-9) = 26 != 0
No
He said I needed to explain it more.
Mad
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Samadhi
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PostPosted: Fri Mar 24, 2006 7:01 am    Post subject: 85 Reply with quote

I also took my Linear Algebra test today. I think I did worse than my calc test. Proofs! Arrrrgggh!
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austinap*
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PostPosted: Sun Mar 26, 2006 7:14 am    Post subject: 86 Reply with quote

I hate it when tests are easy. Test should be hard, otherwise what is there to actually differentiate between A students and students that can just reproduce an answer? I actually seem to do considerably worse in easy classes because the tests don't seem to test actual comprehension of the course material but instead the ability to jump through hoops, and I absolutely hate that. If I'm ever a professor, my tests are going to be insanely hard, but the curve is going to be great. Thats how tests should be. I garantee that I'll know which students really understand the material.
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Samadhi
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PostPosted: Sun Mar 26, 2006 7:42 am    Post subject: 87 Reply with quote

Yeah, but you'd think that out of 15 people, someone should get an A.
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MatthewV
Daedalian Member :_



PostPosted: Sun Mar 26, 2006 8:39 am    Post subject: 88 Reply with quote

I did :-)

I personally feel that tests should also be open-book, open-note, use-anything-you-want. Recognizing how to use the tools and method of thinking you have learned are what I personally find to be important.
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Samadhi
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PostPosted: Sun Mar 26, 2006 10:09 am    Post subject: 89 Reply with quote

I'd be happy to post the test for people to take and report the results (on your honor taking only 1:50).
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Samadhi
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PostPosted: Sun Mar 26, 2006 10:09 am    Post subject: 90 Reply with quote

That is if anyone is interested.
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MatthewV
Daedalian Member :_



PostPosted: Sun Mar 26, 2006 11:08 am    Post subject: 91 Reply with quote

Ouch- almost two hours for tests. My class is an hour each time (4 days a week). He has to make tests that are reasonable to finish in that time frame. This means that I finish in 30 minutes and then can spend 25 minutes working on one problem that doesn't make sense :-)
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:12 am    Post subject: 92 Reply with quote

Let me PM you the test and see how you do. Shouldn't be hard. It's open internet, which is better than open book.
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The Ragin' South Asian
Head Poncho



PostPosted: Sun Mar 26, 2006 11:28 am    Post subject: 93 Reply with quote

take a math test in my free time? where do i sign up?!
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:40 am    Post subject: 94 Reply with quote

Felicitous

I think it's key that time limits are imposed.....so if you are actually interested, PM me and I'll PM you the test.
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CzarJ
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PostPosted: Sun Mar 26, 2006 11:44 am    Post subject: 95 Reply with quote

I'd love to (as worthless as a human being as it makes me feel to admit it), but let me wait until after my calc test on Tuesday. I need all the study time I can get.
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:46 am    Post subject: 96 Reply with quote

Ok, I'll send you a pm, you respond within 5 minutes and I'll send you the test. Time starts 5 minutes after I send.
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CzarJ
Hot babe



PostPosted: Sun Mar 26, 2006 11:48 am    Post subject: 97 Reply with quote

Whaaat? I'm confused. Far too confused to take a test.
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:48 am    Post subject: 98 Reply with quote

Or PM me with a confirmation time and we'll do the above.
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CzarJ
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PostPosted: Sun Mar 26, 2006 11:49 am    Post subject: 99 Reply with quote

How about Wednesday? =P
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:49 am    Post subject: 100 Reply with quote

I'm just trying to set a time limit. Barring IM I don't know a better way to synchronize than through IM. (just trust me)
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:50 am    Post subject: 101 Reply with quote

Whenever or never, your choice.
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CzarJ
Hot babe



PostPosted: Sun Mar 26, 2006 11:50 am    Post subject: 102 Reply with quote

Alright, IM me on Wednesday. =P
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:51 am    Post subject: 103 Reply with quote

You want the practice test?
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CzarJ
Hot babe



PostPosted: Sun Mar 26, 2006 11:52 am    Post subject: 104 Reply with quote

(P.S., we could have done this all through PM, but as I'm sure you've noticed, threadjacking your thread is just about my favorite thing to do, so thanks for the diversion. =P)

Psh, I don't need no stinkin' practice test.
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Samadhi
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PostPosted: Sun Mar 26, 2006 11:55 am    Post subject: 105 Reply with quote

Yeah. That's what I thought.
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Samadhi
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PostPosted: Sun Mar 26, 2006 12:03 pm    Post subject: 106 Reply with quote

Seriously though. Talking with everyone who has been taught by this guy (and there's a few, he's the only one at my 2 year that teaches Calc III or Linear Algebra) he's pretty unsympothetic. Not to say he isn't fair...everything on the tests were in the lectures.

But just imagine your worst homework questions..the ones that make you go ???....those are the questions on the test. Well, not so much calc III, but definitely Linear.
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CzarJ
Hot babe



PostPosted: Sun Mar 26, 2006 12:32 pm    Post subject: 107 Reply with quote

Hehe, I'm curious to see how I'll do without. My last Calc (IV, although the III ones weren't a whole lot better) test was a lot harder than the homework, which I definitely didn't expect.
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Samadhi
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PostPosted: Sun Mar 26, 2006 1:38 pm    Post subject: 108 Reply with quote

I'm curious to see how you do too. Felicitous

I'm about to go to bed though. Pm me tomorrow or whenever when you want to try out the test.
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CzarJ
Hot babe



PostPosted: Sun Mar 26, 2006 5:49 pm    Post subject: 109 Reply with quote

Yeah, I don't know what you were still doing up. I don't know what I was still doing up, either.
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Samadhi
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PostPosted: Mon Apr 03, 2006 5:49 am    Post subject: 110 Reply with quote

I'm getting a 'null pointer exception' on my most recent project. I'm not sure why. I'm going to do this without using an array, but if anyone can tell me why it's doing that, I'd be very happy.

The class used by my program
My program
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Samadhi
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PostPosted: Mon Apr 03, 2006 5:51 am    Post subject: 111 Reply with quote

Oh, I get it when I use the set method. It works fine when I don't use an array.
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CrystyB
Misunderstood Guy



PostPosted: Mon Apr 03, 2006 7:09 am    Post subject: 112 Reply with quote

(disclaimer: i'm doing this in my head, i don't have access to Java right now) i think the reason is that
Code:
PetRecord[] usersPet = new PetRecord[5];
only creates the array, it doesn't initialize ("construct", i.e. call any constructors for) the objects. Therefore, when you call a method (in this case "set") for those objects, there aren't any objects for which that method could work upon...

I guess if you do usersPet[n]=new PetRecord(inputName, inputAge, inputWeight) it will work. *crosses fingers Revenge most foul! *
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Samadhi
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PostPosted: Mon Apr 03, 2006 7:37 am    Post subject: 113 Reply with quote

Perfect! Thanks
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MatthewV
Daedalian Member :_



PostPosted: Mon Apr 03, 2006 7:50 am    Post subject: 114 Reply with quote

I wouldnt mind seeing the test but I doubt I would want to do it as a timed event.

(and I have my own test in a few hours...)
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Samadhi
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PostPosted: Mon Apr 03, 2006 9:01 am    Post subject: 115 Reply with quote

Here ya go.
  1. If f(s,t,u) = s 2 t 3 e u^2st^3 then find all of its partial derivatives.
    1. Determine the distance from the plane 12x + 13y + 5z = 0 to the point (1, 1, -5)
    2. Let a = <2,1,3>, b = <1,3,5>, c = <1,0,6>; Are these vectors coplanar?
    3. Find parametric and vector equations of the line which passes through P 1 (4,5,1) and P 2 (2,1,3).
    4. Find the projection of vector a onto vector c where a and c are from part B above.
    5. Find the equation of the plane that contains the line r(t) = <-1,1,2> + t <3,2,4> and is perpendicular to the plane 2x + y - 3z + 4 = 0

    1. Show that f(x,y) =
      {x 2 /((x 2 + y 2 )^ 1/2 ) if (x,y) != (0,0)
      0 if (x,y) = (0,0)}
      is continuous at (0,0).
    2. Is f(x,y) differentiable at (0,0)?

  2. Find two points on the surface z = 8 - x 2 - 2y at which the tangent plane is parallel to the line x = 3 + 4t, y = 2t, z = 2 + t
  3. Find the directional derivative of f(x,y) = 2xy - y/x at (1,2) in the direction of a vector v = <2,1>
  4. Find D(f o g) if f(u, v) = (uv, u 2 - v 3 , v - u) and g(x,y) =(u(x,y), v(x,y)) where u(x,y) = e x+y and v(x,y) = x+y at the point (x,y) = (2,1)
  5. Find the equation of the tangent plane aqnd the normal vector to the following:
    1. 3xy 2 + z 2 = 10 at (2,1,-2)
    2. z = f(x,y) = ye x^2 + y^2 at (3,2)

  6. Find the equation for the tangent line and a normal vector to the curve defined by:
    1. x 2 + y 2 = 6 at (2,1)
    2. y = f(x) = 45/x 2 at ((5^1/2)/9)
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Antrax
ESL Student



PostPosted: Mon Apr 03, 2006 9:53 am    Post subject: 116 Reply with quote

1. It's not. I do nothing.
_________________
After years of disappointment with get rich quick schemes, I know I'm gonna get rich with this scheme. And quick!
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Samadhi
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PostPosted: Mon Apr 03, 2006 10:00 am    Post subject: 117 Reply with quote

Here's my linear algebra test.

    1. Find the standard matrix representation A of the linear operator
      T: R 3 ----> R 3
      that rotates a vector 30 degrees counterclockwise about the z-axis and then dialates that vector by a factor of 2.
    2. Show that 2 is an eigenvalue of the Linear operator T above and then find its corresponding eigenvector.

  1. Let S = {v 1 , v 2 , v 3 } where v 1 = <2, 0, -1>, v 2 = <1, 5, 0>, v 3 = <0, 3, 1>, where B = {e 1 , e 2 , e 3 } is the standard basis for R 3
    1. Show that S is a basis for R 3
    2. Find (u) S where (u) B = <7, 5, 2>

  2. For the matrices shown, H is the reduced row echelon form that is row equivalent to A:

    1. express the solution of Ax = b as X = Xh + p with p satisfying Ap = b and Xh satisfies the corresponding homogeneous system.
    2. In the Ax = b system above, which variables are restricted and which are free?
    3. Prove that the set of all vectors x in R 4 satisfying the homogeneous system is a subspace of R 4 . What is a basis for this subspace? What is its dimension?

  3. Determine a basis for the subspace of R 3 given by the plane 3x -2y + 5z = 0.
  4. Let T: V ---> V' be a linear transformation. We know that the set of all v in V such that T(v) = 0, the zero vector in V, is a subspace of V. This subspace is called the kernel of the transformation T (or the vector space of solutions of transformations standard matrix homogeneous system).
    Show that if a linear transformation has only the zero subspace as its kernal then it is a one to one transformation.
  5. Find the elementary matrices E i so that the following matrix A can be written as R = E n E n-1 ....E 1 A where R is the row reduced echelon form of A

  6. Suppose that T: R 2 ----> R 2 given by

    Prove that T is one to one.
  7. Evaluate det
    Code:
    1  3  5
    4 14 12
    9  2  0

    by reducing the matrix to row echelon fom.
  8. Find the equation of the plane that contains the line L: <2 + 5t, 1-t, 2 +2t/3> and is perpendicular to the plane 2x + 11y + 3z = 5
  9. Let S = {v 1 , v 2 , v 3 } where v 1 = <2, 0, 0>, v 2 = <1, 2, -2>, v 3 = <2, 1, 1>. Does S span R 3 ? Prove your answer.
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Samadhi
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PostPosted: Mon Apr 03, 2006 10:01 am    Post subject: 118 Reply with quote

Antrax wrote:
1. It's not. I do nothing.
?? It's not what?
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Antrax
ESL Student



PostPosted: Mon Apr 03, 2006 10:14 am    Post subject: 119 Reply with quote

Samadhi wrote:
If f(s,t,u) = s 2 t 3 e u^2st^3 then find all of its partial derivatives.
It's easy to show that, in fact, f(s,t,u) != s 2 t 3 e u^2st^3 . The prefix is false, so I choose to do nothing. Now give me credit.
_________________
After years of disappointment with get rich quick schemes, I know I'm gonna get rich with this scheme. And quick!
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Samadhi
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PostPosted: Mon Apr 03, 2006 10:16 am    Post subject: 120 Reply with quote

I feel *wooshed*
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